The complexity and state space of the Poker is not large. Therefore it is possible to just exhaustively search all the combinations. In fact you can even calculate the probability of getting each cards with some arithmetic. I would recommend you to read Poker Theory and Analytics by Kevin Desmond on MIT Open Courseware to … Read more
“Stack overflow” means that your recursive function calls itself too many times than the system can support it. Either you have an error, and recursion goes to infinity, or the function is correct, but just needs the depth that system currently can’t provide. We cannot tell which of the two is it until we see … Read more
The question is ambiguous, since there’s two reasonable ways of interpreting “repeated digit”. First, a number has a “repeated digit” if it has the same digit twice or more in succession. For example 12334 has a repeated digit (3). Second, a number has a repeated digit if the same digit appears twice. So 1231 would … Read more
You could first think about how many operations it would cost to get all values to the highest value in the list. In a second step you can think if there could be a better solution if you try to reach highest-value+1, highest-value+2, highest-value+3, highest-value+4 . solved This question is asked in a coding test. … Read more
The functions execute different mathematical operations: round() rounds a float value to the nearest integer. If either of the two integers on either side are equal distance apart, the even number is picked. Here, the nearest integer is always -6; for -5.5 the nearest even integer is -6, not -5. math.ceil() returns the smallest integer … Read more
If I was coding this myself (rather than trying to explain a method for someone else to code this) I would do the following: Type ValueAndLevel dataValue As String dataLevel As Long End Type Dim myData() As ValueAndLevel Sub Export1() ReDim myData(1 To 1) ‘Start the process in column 1, with level being 0 Process … Read more
The problem is actually like counting in base sizeof(set) on length k (assuming the set has 10 items maximum). For instance, with a set of { 0, 1, 2 } on length 2, you count from 00 to 22, base 3. To solve the “one digit change only” constraint, instead of counting increasingly, do that … Read more
algorithm for finding the number of 1s in a matrix (only vertical 1s). The image is self explanatory that what i exactly want solved algorithm for finding the number of 1s in a matrix (only vertical 1s). The image is self explanatory that what i exactly want
This can be solved in Dynamic Programming (DP) by following the recursive formula: D(x) = INFINITY x < 0 D(0) = 0 D(x) = min{ D(x-1), D(x-15), D(x/2) } + 1 In bottom-up DP it will be something like: (pseudo code) D = new int[151] D[0] = 0 for (int i = 1; i <151; … Read more
Solution without linq: int[] array1 = new int[] { 3, 5, 6, 9, 12, 14, 18, 20, 25, 28 }; int[] array2 = new int[] { 30, 32, 34, 36, 38, 40, 42, 44, 46, 48 }; int count1 = array1.Length; int count2 = array2.Length; int[] arrayResult = new int[count1 + count2]; int a = … Read more
Your code is not right: it does not do a stable partition of the array. Imagine your array is 100, 33, 333, 22, 222, 11 After the stable partitioning around the first element, it should become 33, 22, 11, 100, 333, 222 // 33, 22, and 11 in the same order as in the original … Read more
Create an algorithm that asks the user for two positive numbers, call them “first” and “last”, and prints the sum of all the numbers between first [closed] solved Create an algorithm that asks the user for two positive numbers, call them “first” and “last”, and prints the sum of all the numbers between first [closed]
First, here’s the solution based on this answer: https://stackoverflow.com/a/57344801/3807365. Explanation below. const paths = [“src”, “src/components”, “src/components/index.ts”, “src/utils”, “src/configuration/config.ts”, “another/file.ts”]; let agg = { temp: [] }; paths.forEach(path => { path.split(“https://stackoverflow.com/”).reduce((agg, part, level, parts) => { if (!agg[part]) { agg[part] = { temp: [] }; agg.temp.push({ id: parts.slice(0, level + 1).join(“https://stackoverflow.com/”), level: level + 1, … Read more
Following is a way to do it in O(nlogn) :- int newarr[]; MinHeap heap; heap.push(0); for(int i=1;i<n;i++) { while(arr[heap.top()]<arr[i]) { k = heap.pop(); newarr[k] = arr[i]; } heap.push(arr[i]); } // No larger elements while(!heap.isEmpty) { k = heap.pop(); newarr[k] = -1; } Time Complexity : There are only n inserts and n deletes possible in … Read more
You’re incorrectly printing the node’s value twice. You don’t need to check node->mid, as this is checked inside inorder(node->mid);. inorder(node) { if (node) { inorder(node->left); print(“%d “, node->value); inorder(node->mid); inorder(node->right); } } 0 solved Recursive and non-recursive traversal of three degree tree