[Solved] Variable Buffer?

Question

You’re hitting undefined behavior for the below line

 result = result*num;

as you’ve not initialized result. The initial value for an uninitialized automatic local variable is indeterminate. Using that invokes UB.

Always initialize your local variables, like

 int count = 0 , result = 0 ; //0 is for illustration, use any value, but do use

Then coming to the case, where you want to change all ints to float, only changing the data type of the variable is not sufficient. You need to change the corresponding format specifiers, too.

Accepted Answer

You’re hitting undefined behavior for the below line

 result = result*num;

as you’ve not initialized result. The initial value for an uninitialized automatic local variable is indeterminate. Using that invokes UB.

Always initialize your local variables, like

 int count = 0 , result = 0 ; //0 is for illustration, use any value, but do use

Then coming to the case, where you want to change all ints to float, only changing the data type of the variable is not sufficient. You need to change the corresponding format specifiers, too.