[Solved] Unrectified image from unwrapping a truncated cone

Question

You have to project your image coordinates to a 2d plane. For a cone you could proceed like this:

For a simple approach you could ignore the fact that it’s a truncated cone and treat it like a cylinder. For each point (alpha,r,z) on the cone calculate the angle alpha, distance r and height z. For a simple projection use alpha on the x and z on the z axis.

Your example image does not look like such a projection of a cylinder, rather it looks like the unwinding of a truncated cone. To implement this you must know the geometry of the full cone. If you know the geometry of each point, you need to calculate the distance from the cone tip S and the angle alpha. Example

Accepted Answer

You have to project your image coordinates to a 2d plane. For a cone you could proceed like this:

For a simple approach you could ignore the fact that it’s a truncated cone and treat it like a cylinder. For each point (alpha,r,z) on the cone calculate the angle alpha, distance r and height z. For a simple projection use alpha on the x and z on the z axis.

Your example image does not look like such a projection of a cylinder, rather it looks like the unwinding of a truncated cone. To implement this you must know the geometry of the full cone. If you know the geometry of each point, you need to calculate the distance from the cone tip S and the angle alpha. Example