[Solved] Too many arguments to function call, What do I do?

Question

In your function definition

float remainingAngle(float answer)

the function remainingAngle() accepts one parameter.

OTOH, in your function call

remainingAngle(angleA,angleB);

you’re passing two arguments.

The supplied argument number and type should match with the parameter list in function definition.

That said, your code is wrong.

Point 1. Your local variables will shadow the global ones. Maybe that’s not what you want. Change
```
float angleA = 30.0;
float angleB = 60.0;
```
to
```
 angleA = 30.0;
 angleB = 60.0;
```

Point 2. The function

float remainingAngle(float answer)
{
    float answer= angleA+angleB;
//redefinition of answer
 return 0;
}

is logically wrong. It should rather be

float remainingAngle(void)
{
    float answer= angleA+angleB;
    return answer;
}

and should be called like

float angleC = remainingAngle();

AFTER EDIT:

as per your requirement, you can do

float remainingAngle(float angleA, float angleB)
{
    float answer= angleA+angleB;
    return answer;
}

However, this makes the global variables useless.

Accepted Answer