[Solved] Storing Char and using it in if-statements

by


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You could do something like this:

#include<stdio.h>

int main(void){
    int int1, int2, sum=0;
    char op;


    printf("Please enter one of the following Operators [*] [/] [+] [-]   ");
    if((scanf("%c",&op)) != 1){
        printf("Error\n");
    }

    printf("Enter Value Here: ");
    if((scanf("%d", &int1)) != 1){
        printf("Error\n");
    }

    printf("Enter Value Here: ");
    if((scanf("%d", &int2)) != 1){
        printf("Error\n");
    }

    if (op == "https://stackoverflow.com/"){
        sum = int1 / int2;
    }else if(op == '*'){
        sum = int1 * int2;
    }else if(op == '+'){
        sum = int1 + int2;
    }else if(op == '*'){
        sum = int1 - int2;
    }

    printf("The sum is %d\n", sum);

    return 0;
}

Edit:
For a better precision you can use float or double, Use double if you are not sure.

#include<stdio.h>

int main(void){
    float int1, int2, sum=0;
    char op;


    printf("Please enter one of the following Operators [*] [/] [+] [-]   ");
    if((scanf("%c",&op)) != 1){
        printf("Error\n");
    }

    printf("Enter Value Here: ");
    if((scanf("%f", &int1)) != 1){
        printf("Error\n");
    }

    printf("Enter Value Here: ");
    if((scanf("%f", &int2)) != 1){
        printf("Error\n");
    }

    if (op == "https://stackoverflow.com/"){
        sum = int1 / int2;
    }else if(op == '*'){
        sum = int1 * int2;
    }else if(op == '+'){
        sum = int1 + int2;
    }else if(op == '*'){
        sum = int1 - int2;
    }

    printf("The sum is %.1f\n", sum);

    return 0;
}

4

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solved Storing Char and using it in if-statements