What happens to
b?
Nothing happens to b.
When you do
a = b;
you’re copying the value stored in b and putting it in a. (You’re not making a an alias of b.)
When you then do a += 1; you’re changing the value stored in a (and the value stored in b remains unchanged).
You can verify this by printing the final values after your code snippet:
System.out.println(a); // prints 8
System.out.println(b); // prints 7
What happens if you change the variable
b, or what if you changea. What does the order have to do with anything.
a and b are two independent variables and changing one will never affect the other.
The order matters since when you do a = b the value of b is copied into a and whatever a stored before is discarded. If you had done a += 1 prior to a = b, then a would have been restored to 7 again.
2
solved If a = b, what happens if each value changes respectively?