[Solved] How to check how many times one number appears in the second number? [closed]

by 


int count=0;
if((second%10)==first){ 
    count++;
}
if(Math.round((second/10))==first){
    count++;
}
System.out.println(first+" occurs "+count+" times in "+second);

Maybe this can help you ;), replace your last println by this 8 lines 😉

but as shmosel sait in comment, be carreful it’s 

int first = n.nextInt(10);

int second = n.nextInt(90)+10;

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solved How to check how many times one number appears in the second number? [closed]