[Solved] How can I do an average reverse in c#? [closed]

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Here is a method that will do just that.

public double[] AverageReverse(double targetAverage, double range)
{
    var r = new Random(); // TODO: Cache it between calls to avoid "why does ny Random class only produce the same numbers?"
    var n1 = targetAverage - r.NextDouble() * range;
    var n2 = targetAverage + r.NextDouble() * range;
    var n3 = 3 * targetAverage - (n1 + n2);

    return new[] { n1, n2, n3 };
}

Example:

var ar = AverageReverse(3.92, 0.5);
// returns (example):
//   3,76575929136284 
//   3,98495292557634 
//   4,00928778306082 
// average:
//   3.92

The way it works is that by solving the following equation:

average = (n1 + n2 + n3) / 3

for n3 gives:

    average             = (n1 + n2 + n3) / 3
3 * average             =  n1 + n2 + n3
3 * average - (n1 + n2) =            n3

thus:

n3 = 3 * average - (n1 + n2)

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solved How can I do an average reverse in c#? [closed]