[Solved] How can i create dynamically allocated array In C [duplicate]

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Assuming you have the number of rows “r” and the number of columns “c”, you can do this:

int **arr;
arr = malloc(r*sizeof(int*));
for(int i=0; i < r; i++)
{
    arr[i] = malloc(c*sizeof(int));
}

this dynamically allocates an array of pointers to integers, and then allocates arrays of integers to each pointer. Don’t forget to delete dynamically allocated arrays when you’re done, in this case you should delete the integer arrays first and then the pointer array:

for(int i=0; i < r; i++)
{
    free(arr[i]);
}
free(arr);

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solved How can i create dynamically allocated array In C [duplicate]