I have a feeling that you are requiring a formula to get number of iteration the nested loops will.
for( i = 1; i <= n; i++ )
for ( j = i+1; j <= n; j++ )
for( k = j+1; k <= n; k++ )
For those loops, the number of iterations will be:
(n*(n-1)*(n-2))/6, where n > 2.
Generic formula for above kind nested loops:
(n*(n-1)* ... *(n-r+1)) / r!, where n > r-1.
Here, r = number of nested loops
For example: when n = 20 and r = 3, number of iterations will be = (20*19*18) / 3! = 1140
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solved Formula for counting loop iteration