You want to create an array with a size of zero which is not allowed. You also can´t declare an array with a variable size so you have to use malloc
or something else.
#include <stdio.h>
#include <stdlib.h>
int main()
{
printf("HOW MANY NUMBERS DO YOU WANT TO INPUT\n");
int array_size;
scanf("%d", &array_size);
int* Array = (int *) malloc(array_size * sizeof(int));
for(int index = 0; index < array_size; index++)
{
printf("inputs left: %d\n", array_size - index);
scanf("%d", (Array + index));
}
for(int i = 0; i < array_size; i++)
{
printf("%d\n\r", *(Array + i));
}
free(Array);
return 0;
}
Which gives
HOW MANY NUMBERS DO YOU WANT TO INPUT
3
inputs left: 3
1
inputs left: 2
2
inputs left: 1
3
1
2
3
Or you use something like an std::vector
.
#include <stdio.h>
#include <vector>
int main()
{
printf("HOW MANY NUMBERS DO YOU WANT TO INPUT\n");
int array_size;
scanf("%d", &array_size);
std::vector<int> Array;
for(int index = 0; index < array_size; index++)
{
int Temp;
printf("inputs left: %d\n", array_size - index);
scanf("%d", &Temp);
Array.push_back(Temp);
}
for(int i = 0; i < array_size; i++)
{
printf("%d\n\r", Array.at(i));
}
return 0;
}
Which result in the same output.
4
solved For loop not working properly to get inputs in an array in c [closed]