[Solved] class->methode1()->methode2() what does it mean? [closed]

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class->methode1() returns a pointet to an object that provides a method methode2 you can call immediately. By doing this you create anonymous objects (rvalues if I am not wrong) and you call methods on those objects. You cannl actually say

class2 = class1->methode(); and then call class2->methode2(); to achieve the same. (pseudo-code)

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solved class->methode1()->methode2() what does it mean? [closed]