[Solved] C: Weird conditional printf behavior [closed]

by


There is one semicolon after the if statement that is causing the problem.

if (i!=0);
{
     //this will always execute
}

change it to

if (i!=0)
{
  //this will execute if i != 0
}

The compiler does not warn you because the first statement is syntactically valid.

solved C: Weird conditional printf behavior [closed]