[Solved] C++ random bitwise behavior

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When

n++ & 1

executes, lets expect n is odd number at the moment, condition is true.

Post incrementation is applied and n is even when

result += n

executes. Thats why its counting even numbers instead of odd. Modify code to

while(n < 99) result += !(n++ & 1) ? n : 0;

and it will count odd one’s.

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solved C++ random bitwise behavior