[ad_1] The error is here: if($admin_username && $admin_password && $admin_token == session_id()) It seems quite likely this is line 63. The problem is you are only defining $admin_username if $_SESSION[‘admin_username’] is set. Although you don’t show it in your code example, I’d presume that the same thing is true of $signin_username. Solution #1 – use … Read more
[ad_1] You may try this to select data “SELECT * FROM table_name WHERE bought BETWEEN 50 AND 100 ORDER BY bought ASC” 5 [ad_2] solved select all data to a database between results = 1 to 100 [closed]
[ad_1] A simple approach is using string.Split() to split the words by white-space, take two words via Enumerable.Take and then join them with white-spaces again: string firstTwoWords = string.Join(” “, text.Split().Take(2)); Remember to add using System.Linq; Demo [ad_2] solved How can I substring word in C#
[ad_1] I didnt understood your question properly but i think this is what you need… $where=”‘code=”.$cod.”‘”; Or $where=”code=””.$cod.”””; 2 [ad_2] solved How do i use variable within a variable second variable value give single qutaion? [closed]
[ad_1] there are shorthand echo statements that looks like: <?=$_GET[1]?> although you must have this feature turned on. short-open-tag 3 [ad_2] solved Alternative to “echo” withe less code/characters? [closed]
[ad_1] Linux has a system-wide shceduler called cron. It is very probably already installed. More information here: http://en.wikipedia.org/wiki/Cron 3 [ad_2] solved How to call a method of any php class via linux server [closed]
[ad_1] var obj = jQuery.parseJSON( lines ); this will produce an array. … .append( obj + ‘<tr … this will convert the array to string that looks very much like this: ‘…</tr>,<tr …’ before appending your new row. If you want to concatenate the elements of the string client-side (why not do it server-side?), you … Read more
[ad_1] var regex = /[0-9a-zA-Z$_]+/ig For more information see here https://developer.mozilla.org/en-US/docs/JavaScript/Guide/Regular_Expressions 1 [ad_2] solved Javascript : To text string contains only alpha numaric,$ and _ [closed]
[ad_1] If we use a valid URL instead of wow (say, http://example.com/wow), the result is http://example.com/3, which is correct: The 2 replaces the wow, and the 3 replaces the 2. This is how relative URLs work. If you want to stack them and get http://example.com/wow/2/3, you need / at the end of wow and 2: … Read more
[ad_1] Taken from here The contract between equals() and hashCode() is: 1) If two objects are equal, then they must have the same hash code. 2) If two objects have the same hash code, they may or may not be equal. Therefore: any class that defines equals() differently than this == other must have its … Read more
[ad_1] if(x==0) Since x doesn’t exist, it throws a ReferenceError here and aborts the rest of the function. You need to declare x first. This: function Xyz() { var x=0; } Creates a variable x that is local to the function and Is never called anyway [ad_2] solved Javascript – novice script not working
[ad_1] Answer link : NoClassDefFoundError below SDK 21 I resolved the issue by adding this to my Application Class. @Override protected void attachBaseContext(Context base) { super.attachBaseContext(base); MultiDex.install(this); } If you don’t have/use Application class, you can put this: android:name=”android.support.multidex.MultiDexApplication” Into your tag on AndroidManifest.xml If you already have implemented an Application class Also obviously, you … Read more
[ad_1] If you are using swift 3, you should animate like this: UIView.animate(withDuration: 0.5) { // You code that will be animated } You are missing the {}. [ad_2] solved My Xcode keeps sending an error and I can’t seem to fix it
[ad_1] You need to define a flag which will be set after the first find. void delete (int s[] , int &top , int v) { bool found = false; int ts[size] ; int ttop=-1; while(top!=-1) { if (s[top]!=v) { push(ts,ttop,s[top]); } else { if (found == false) { found = true; push(ts,ttop,s[top]); } } … Read more
[ad_1] See it yourself : void LoginScreen(){ //you still want to use addUser from main, so what is this ? UserInfo addUser[100]; ———–+ … | } | | void main() | { | | UserInfo addUser[100]; ————+ … } You can do something like this : void LoginScreen(UserInfo addUser[] ){ … } Obviously you need … Read more