Kirat[ad_1] The use of parent.Bottom is indicative that an iframe named “Bottom” exists within the page. Based on that, you can assume that the method changeDiv() is setting this iframe’s content to Intro.asp, and that proceed() is submitting a form called frmChange within that iframe. I would also add that the MM_ methods are not … Read more
[ad_1] I need to get process name from process id in windows to find process names associated with a logged event. If you are getting the Process ID from a log, it will only be valid if the original process is still running. Otherwise, the ID is no longer valid for that process name. If … Read more
[ad_1] Solution (w is the responseWriter) str := “{\”key1\”:{\”key2\”:\”value1\”,\”key3\”:\”value2\”}}” w.Write([]byte(str)) 2 [ad_2] solved Encode arbitrary string to JSON in http response
[ad_1] It is completely up to the implementation. For example, const data on bare metal ARM uCs is stored in the FLASH memory. You can write to there but it will have no effect at all. Hosted systems will behave differently depending on the OS, its version and hardware. How can I overwrite a const … Read more
[ad_1] Here you go: <?php $array = array( array(1,2), array(3,4), array(5,6), array(7,8) ); function processArray(&$array) { for ($i = 0; $i < count($array); $i++) { if ($array[$i][0] > 4) { $array[$i][0] = $array[$i][0] – 3; } if ($array[$i][1] < 5) { $array[$i][1] = $array[$i][1] + 3; } } } processArray($array); print_r($array); Outputs: Array ( [0] … Read more
[ad_1] You have to count only owners id with DISTINCT word, which counts only unique owners. SELECT owners.city, count(DISTINCT owners.id) AS ‘Owners’ FROM owners INNER JOIN dogs ON (owners.id = dogs.owner_id) GROUP BY owners.city 1 [ad_2] solved Mysql Query [0001]
[ad_1] I ran your code through the NAG Fortran Compiler (on Linux). The version you have posted doesn’t compile for me: > nagfor -mtrace=all -u -C=all -C=undefined valuefuncmat.f90 … Error: valuefuncmat.f90, line 100: Syntax error detected at )@, … That of course is easy to rectify (i.e., change line 100 to write(*,'(20G12.4)’) vOUT(i,:)). With that … Read more
[ad_1] Use Time::Piece. It’s a standard part of the Perl distribution. Use strptime (string parse time) to parse your string into a Time::Piece object. Then use strftime (string format time) to display your Time::Piece object in whatever format you want. #!/usr/bin/perl use strict; use warnings; use 5.010; use Time::Piece; my $in_format=”%Y-%m-%d %H:%M:%S”; my $out_format=”%Y-%m-%dT%H:%M:%SZ”; my … Read more
[ad_1] int a[5] a is an array of 5 int. int (*a)[5] a is a pointer to an array of 5 int. int a[5][4] a is an array of 5 array of 4 int. int *a[5] a is an array of 5 int pointers. 6 [ad_2] solved What’s the difference between “int a[5]” and int … Read more
[ad_1] You can use an extension method like this public static class StringExtensions { private static char[] _alphabet; static StringExtensions() { _alphabet = “abcdefghijklmnopqrstuvwxyz”.ToCharArray(); } public static bool ContainsAlphabet(this string input) { return !_alphabet .Except(new HashSet<char>(input)) .Any(); } } “asdasd”.ContainsAlphabet(); //false “abcdeffffghijklmnopqrstuvwxyzzz”.ContainsAlphabet(); //true 0 [ad_2] solved Check if the string contains all the characters from … Read more
[ad_1] You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near at line 1 [ad_2] solved You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use … Read more
[ad_1] Problem is in your odbc connection goto ControlPanel->AdministrativeTools->DataSource(ODBC)->System DSN->ADD->SqlServer-> then in the name field give the Source Name. you have to use this name instead of testdb in your DriverManager.getConnection method. Because getConnectionMethod take the source name not the database name. so your code is not working. However after filling the source name fill … Read more
[ad_1] You need two nested foreach loops. One iterates the ebles the inner one the elements in each list. The innermost loop contains a yield return element; This is the outline. Now go and read about each of the words mentioned in this outline. [ad_2] solved C# Enumerable yield and foreach [closed]
[ad_1] There are a few things that could be wrong. Primarily, you do need to modify the DESCRIPTION file to include LinkingTo: Rcpp, RcppArmadillo and ensure that #include <RcppArmadillo.h> is present in each .cpp file in the /src directory. You will also need to include two Makevars files. Makevars.win and Makevars with: PKG_LIBS = $(LAPACK_LIBS) … Read more
[ad_1] A working variation of my solution appears below. The reason I had to do it this way is because while I was able to dereference (**Array)[MAX_FILENAME_AND_PATHNAME_LEN] I was only able to modify the first string array in the array. The string array was initialized and filled several strings. While I could reference a string … Read more