Kirat[ad_1] for(int i = 0; ; i++) When does your loop end?!?!? Your second condition in for (the testing expression) is evaluated as true (at least as long as i<4). You need for(int i = 0; i < 4 ; i++) Otherwise it may break anytime after i>=4, but not before, since all components of … Read more
[ad_1] You can split the list by a comma delimiter and validate each individual element. $.each(enteredData.split(“,”), function(i, str){ var esnList = +str; /* enter validation here */ }); 2 [ad_2] solved How can I make jQuery to check multiple values?
[ad_1] Create HashMap, put to this map all chars from first word with zero value. After that iterate over chars in second word and if this chars contains in map then increase map value for this char. Map<Character, Integer> map = new HashMap<>(); for(char c: word1.toCharArray()) { map.put(c, 0); } for(char c: word2.toCharArray()) { Integer … Read more
[ad_1] Let’s try to understand the code step by step. First of all, we call the function solution(), which is what leads to the execution of the puzzle answer. Solution funcion: public void solution() { int y = 0; b[0] = -1; while (y >= 0) { do { b[y]++; //if last cell was unsafe … Read more
[ad_1] Tesseract is the Open source library . So I dont thing it is much accurate . OCR libraries gives better results for images with resolution more than 150px . Also it would be nice if you give Black and white image . If you are more interested in accuracy then you have to find … Read more
[ad_1] Designate a register to be a counter (pick any one you aren’t using for other stuff) and set its value to 0. When you hit a * character, push characters onto the stack until it finds a blank, incrementing the counter with each push. When a blank is found, pop characters off the stack, … Read more
[ad_1] Use php for different repeating section of your pages, like create separate php pages for nav, footer, or contact and use it multiple times or where you need by using php include statement like <?php include(‘nav.php’);?> //to include nav section And for your second question, YES, there is a way to that, With .htaccess … Read more
[ad_1] You will need to escape the quotation mark you require in the string; std::string str(“Q850?51’18.23\””); // ^ escape the quote here The cppreference site has a list of these escape sequences. Alternatively you are use a raw string literal; std::string str = R”(Q850?51’18.23″)”; The second part of the problem is dependent on the format … Read more
[ad_1] Yes, signed integer overflow has undefined behavior in C. i > INT_MAX is never true for any int i. How can you have an int greater than the maximum possible int? [ad_2] solved Strange behaviour when intentionally assigning `i` value greater than INT_MAX [duplicate]
[ad_1] You want to display distinct values of Department Number and Department Name You join Employees table with Department on Department Number You join Jobs table with Employees on Job ID You filter the result by excluding those Department Numbers of the entire Employee table that have a Job ID matching the pattern %SA_REP% In … Read more
[ad_1] You can use break. It breaks the loop you are in right now. Plus, in your condition you should use else if rather than multiple if. foreach (var pair in firstStrings) { foreach (var pair2 in secondStrings) { if (secondStrings.ContainsKey(pair.Key)) { LogMessage( pair.Value + ” <———-> ” + pair2.Value + ” On Line ” … Read more
[ad_1] *(num+1)[1] and **(num+2) are different ways of writing the same thing. That is, the third element of num. The type of num is short (*)[2]. That is, it is a pointer to an array of 2 short values. With these two facts in mind we can work out what the code is doing. Below … Read more
[ad_1] I think this is what you want: JavaScript : UPADTE JSFiddle : DEMO function mynew() { var myDiv = document.getElementById(‘mydiv’); var contents = myDiv.innerHTML.split(” “); var modText=””; for (var i = 0; i < contents.length; i++) { modText += ‘<span>’ + contents[i] + ‘</span> ‘; } myDiv.innerHTML = modText; window.onclick = myFunction; function myFunction(e) … Read more
[ad_1] You need to put your code within the for block. Remove the semicolon For(i=1;i<=num;i++) { // code here } 2 [ad_2] solved I am thinking about for loop termination is it halts the loop or what’s the actual story [closed]
[ad_1] First use the method described here to retrieve all hrefs, then you can use a regex or strpos to “filter out” those who don’t start with /download/. The reason why you should use a parser instead of a regex is discussed in many other posts on stack overflow (see this). Once you parsed the … Read more