[Solved] Extracting the values within the square braces

by


In GNU awk:

$ awk -F"[][]" '{split($2,a,"-"); for(i=a[1];i<=a[2];i++) print $1 i $3}' file
app-server-l112.test.com
app-server-l113.test.com
app-server-l114.test.com
app-server-l115.test.com
server-l345.test.com
server-l346.test.com
server-l347.test.com
server-l348.test.com
dd-server-l2.test.com
dd-server-l3.test.com
dd-server-l4.test.com
  • split to fields by [ and ] using FS
  • use split the get the range start (a[1]) and end (a[2])
  • iterate the range with for and output

There is no checking whether there was a range or not. It could be implemented with something like: print (NF==3 ? $1 i $3 : $1 ).

solved Extracting the values within the square braces