To start, we’ve seen no numbers, and the code assumest the biggest is 0 or larger:
var biggest = 0;
We’ll look at each number in the list:
for(i=0; i < num.length; i++ ) {
Is the current number bigger than the biggest we’ve seen?
if( num[i] > biggest ) {
If so, it’s the new biggest number
biggest = num[i];
}
}
When the loop is done, biggest
contains the largest number we saw along the way.
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solved Javascript – biggest number from array using loop [closed]