[Solved] const char* if() comparison with “SRAD” returns false [duplicate]

Introduction

This question is related to the comparison of const char* if() with “SRAD” and whether it returns false. The const char* if() comparison is a type of comparison used in C++ programming language. It is used to compare two strings and determine if they are equal or not. In this case, the comparison is between the const char* if() and the string “SRAD”. This question will discuss the details of this comparison and why it returns false.

Solution

This question is a duplicate and has already been answered.

The answer is that the comparison of a const char* with “SRAD” will return false because the const char* must be a null-terminated string of characters, and “SRAD” is not a null-terminated string.

if(strcmp("SRAD", name) == 0)

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The comparison of a const char* with the string literal "SRAD" will always return false. This is because a const char* is a pointer to a character array, while a string literal is a pointer to a constant character array. The two are not the same type, and therefore cannot be compared.

In order to compare a const char* with a string literal, you must use the strcmp() function. This function takes two parameters, both of which must be of type const char*. It will then compare the two strings and return 0 if they are equal, or a non-zero value if they are not.

For example, if you have a const char* called str and you want to compare it to the string literal "SRAD", you would use the following code:

if (strcmp(str, "SRAD") == 0)
{
    // The strings are equal
}
else
{
    // The strings are not equal
}

This will compare the two strings and return true if they are equal, or false if they are not.