[Solved] Different output on recursive call using static variable [closed]

by


  1. static int n = 0; is one time initialization

Like the snippet below,

bool initialized = false;
static int n;

int fun1(int x){
  if(!initialized){
    n = 0;
    initialized = true;
  }
  if(x > 0){
    n++;
    return fun1(x-1)+n;
  }
  return 0;
}
  1. static int n; n =0 is reset to zero on every recursive call. Like below,
bool initialized = false;
static int n;
int fun(int x){
  if(!initialized){
    n = 0;
    initialized = true;
  }
  n = 0;
  if(x > 0){
    n++;
    return fun(x-1)+n;
  }
  return 0;
}

In reality n is part of .BSS and initialized to zero at load time.

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solved Different output on recursive call using static variable [closed]