[Solved] How do I remove all strings containing digits before “hs” like “18hs” from a list of strings? [closed]

by 


>>> import re
>>> words = ["hello", "18hs", "18aaa", "21hr"]
>>> [w for w in words if not re.match(r'\d+h', w)]
['hello', '18aaa']

This loops over the list and keeps the items that don’t match the regex \d+h, which means “one or more digits followed by an h”.

If you need to keep strings like 7hg, use a more specific regex, \d+h(s|r)?$, which means “one or more digits, h, optional s or r, end of string”:

>>> words = ["hello", "18hs", "18aaa", "21hr", '7hg']
>>> [w for w in words if not re.match(r'\d+h(s|r)?$', w)]
['hello', '18aaa', '7hg']

Also note that re.match automatically matches the start of the string, so it’s like an implicit ^ at the start of the regex.

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solved How do I remove all strings containing digits before “hs” like “18hs” from a list of strings? [closed]