[Solved] Error: else without if. What went wrong? [closed]

by


You should do it with a switch : 

public static void main(String args[])
        {
            System.out.println("Enter 1 to Add, 2 to Subtract, 3 to Divide, or 4 to Multiply");
            int x = keyboard.nextInt();

    switch(x){
            case 1:

                System.out.println("Enter an integer");
                int num1 = keyboard.nextInt();

                System.out.println("Enter another integer");
                int num2 = keyboard.nextInt();

                System.out.println("The sum of the numbers equals " + (num1+num2));
            break;
            case 2:

                System.out.println("Enter an integer");
                num1 = keyboard.nextInt();

                System.out.println("Enter another integer");
                num2 = keyboard.nextInt();

                System.out.println("The sum of the numbers equals " + (num1-num2));
            break;
            case 3:

                System.out.println("Enter an integer");
                num1 = keyboard.nextInt();

                System.out.println("Enter another integer");
                num2 = keyboard.nextInt();

                System.out.println("The sum of the numbers equals " + (num1/num2));
            break;
            case 4:

                System.out.println("Enter an integer");
                num1 = keyboard.next=Int();

                System.out.println("Enter another integer");
                num2 = keyboard.nextInt();

                System.out.println("The sum of the numbers equals " + (num1*num2));
            break;
            default:

                System.out.print("Error 510038585832857329457294547243344684643734");
            break;
        }
    }

}

2

solved Error: else without if. What went wrong? [closed]