[Solved] How to group a Seq[Array[(Int, Int)]]) by the second value of array

by


Try this

val input = Seq((1,0),(2,0),(2,0),(1,1),(1,1),(2,1))
input.groupBy(_._2).collect{
  case e => e._2.map(_._1)
}
//res3: scala.collection.immutable.Iterable[Seq[Int]] = List(List(1, 1, 2), List(1, 2, 2))

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solved How to group a Seq[Array[(Int, Int)]]) by the second value of array