[Solved] C++ return a list of values? [closed]

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In your code, you declare to return type T, but the variable you return has type list<T>. I’d suggest to develop your code with concrete types (and without templates) first; you can exchange the concrete type with placeholders afterwards, but concrete types give a better idea what actually happens.
Try the following code and translate it then to a template:

list<int> swapList(list<int> &theList)
{
    list<int> li;
    auto start = theList.rbegin(), stop = theList.rend();
    for (auto it = start; it != stop; ++it)
    {
        li.push_back(*it);
    }

    return li;
}

int main()
{
    list<int> source { 1,2,3,4 };
    list<int> swapped = swapList(source);
    for (auto i : swapped) {
        cout << i << " ";
    }
}

solved C++ return a list of values? [closed]