[Solved] Java String.split() without specific symbol [closed]

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You can do that with split() and some regex-magic:

System.out.println( Arrays.toString( "3332255766122".split( "(?<=(.))(?!\\1)" ) ));

Output: 

[333, 22, 55, 7, 66, 1, 22]

Regex breakdown:

  • (?<=x) is a positive zero-width look-behind, so it will match the position right after the match for subexpression x
  • (.) as epxression for x above is a capturing group that matches any character and captures it for the next step. In combination with the part above, i.e. (?<=(.)) this means: “match any position after a character and capture that character into a group”
  • (?!x) is a negative look-ahead which matches any position that is not followed by a match of subexpression x.
  • \1 is a back-reference to the match of the first capturing group ((.) in this case), so in combination with the part above, i.e. (?!\1), this matches any position that does not match the character before

In words the expression would mean: “match any position after any character that is not followed by the same character”.

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solved Java String.split() without specific symbol [closed]