[Solved] String array vs String split array [duplicate]

Question

The reason beeing is the compiler. At compile time the compiler does notice that the literal Hi exists twice in the code and does intern this string for your specific class.
After compilation both of your interned strings Hi are pointing to the same reference of Hi. That´s the reason why the second print results in true.

The split doesn´t know it´s result and creates new references for the corresponding Strings. That´s the reson why Hi from the split and the literal Hi are not using the same reference.

Accepted Answer

The reason beeing is the compiler. At compile time the compiler does notice that the literal Hi exists twice in the code and does intern this string for your specific class.
After compilation both of your interned strings Hi are pointing to the same reference of Hi. That´s the reason why the second print results in true.

The split doesn´t know it´s result and creates new references for the corresponding Strings. That´s the reson why Hi from the split and the literal Hi are not using the same reference.