[Solved] How to bring the footer to the very bottom?
checkout this Sticky Footer However, marquee tag is quite old and you should’nt be used anymore at least with HTML5 0 solved How to bring the footer to the very bottom?
checkout this Sticky Footer However, marquee tag is quite old and you should’nt be used anymore at least with HTML5 0 solved How to bring the footer to the very bottom?
Hello Stephen your edit suggest that start indexes from 0 solved my problem. thanks a lot solved How to post back array of strings from razor view to MVC controller?
Set #container {min-height:400px;} and your problem should be fixed. 7 solved CSS formatting required for obscured HTML footer
Is your server configured to run HTML files as PHP files? You’re trying to run a PHP code inside a HTML file! You should rename index2.html to index2.php and run it inside an Apache server, or configure your Apache to run HTML as PHP. Also, index2 must be the action of index1 form. UPDATE How … Read more
This should do it: My_DICT = {‘Sale_Type’ : ‘Car’, ‘Sale_Length’ : 5, “Query_String” : “”} My_DICT[‘Query_String’] = “select * from Sales where Length > %s” % My_DICT[‘Sale_Length’] — EDIT — Considering your input example, you have a list of dictionaries in My_DICT. You could do it like this: for element in My_DICT: element[‘Query_String’] = “select … Read more
Just change your if condition and remove 1x zero, so from this: if ($number < 10000) { return pm_number_format($number); } to this: if ($number < 1000) { return pm_number_format($number); } Input: 1 12 123 1234 12345 123456 1234567 12345678 123456789 Output: 1 12 123 1.2K //<–See output as you wanted 12.3K 123.5K 1.2M 12.3M 123.5M … Read more
you have an error in your code, there is one closing bracket too much change if (document.form[‘form’][‘name’].value != “” && document.form[‘form’][‘city’].value != “” )) { to if (document.form[‘form’][‘name’].value != “” && document.form[‘form’][‘city’].value != “” ) { 1 solved Javascript – verify empty inputs
You can do it using a replacement map, replacing the character at index 1 if the given code doesn’t start with two letters: using System; using System.Text; using System.Collections.Generic; using System.Text.RegularExpressions; public class Test { private static string[] productCodes = new[] { “MD0133776311I”, “M10133776311I”, “M20133776311I” }; private static Dictionary<char, char> replacementMap = new Dictionary<char, char> … Read more
Please have a look at the org.jfree.demo.TimeSeriesChartDemo1 class that is included in the JFreeChart download. The source code is included in the source download of JFreeChart, so it’s a good point to start with. I think that’s what you want. Update (revised on your comment): You can change the format of axis labels by redefining … Read more
i solved it. Just i forgot setup UITextView Delegate. Thanks. solved Limit number of characters in uitextview – I have 5 text view same page
Add a forward declaration of library_class_1 in header.h before using it. class library_class_1; class header { public: header(); void DoSomething(library_class_1 const& object_1); } Make sure to #include the .h file that defines library_class_1 in header.cc. #include <librarry_class_1.h> void header::DoSomething(library_class_1 & object_1) { // Use object_1 … } 0 solved Access predefined objects in header files
A 2D array does not decay to a pointer to a pointer. By using: maxim=findMax((int **)a,m,n); you are forcing the compiler to ignore your error. Instead of int findMax(int **a,int m,int n) use int findMax(int a[][20],int m,int n) and then, call the function simply using: maxim=findMax(a,m,n); You said: The problem statement says that int findMax(int … Read more
The problem was the way you were trying to increase incorrect. Just use wrong as a boolean that you will use to decide if you need to increase or not incorrect Here’s the solution: #include <stdio.h> #include <string.h> #define SIZE 50 /*prototype definitions*/ int compareString(char *, char *); int main(void){ char word[SIZE]; char input[SIZE]; char … Read more
Your question is quite vague but I think what I’ve done below can at least nudge you in the right direction. Let’s say you have something like this – a div to hold your search results, each of which is it’s own div with class result, and a separate div to hold the ‘moved’ ones: … Read more
In Java, the test if (i==f && i.equals(f)) is nonsensical. Since i is an Integer and f is a Float, they will never be == (and, since they are incommensurate types, cannot legally be compared with ==). For reference types, the == operator evaluates to true only if the variables reference the same object, which … Read more