Nevermind guys, my friend already fixed the problem. He used WebRequest to send and receive the data. He also said, dont forget to escape the string of base64(+, =, /), or the api will not accept properly and will return invalid base64 string. Thanks anyway. solved Upload Image to a Chevereto Website C#
MVC 5 With Tinymce Editor Contain Words “FIND”, “SERVICES” and some more around 8 more letter “ERR_CONNECTION_RESET” solved MVC 5 With Tinymce Editor Contain Words “FIND”, “SERVICES” and some more around 8 more letter “ERR_CONNECTION_RESET”
There are several ways to perform HTTP GET and POST requests: Method A: HttpClient (Preferred) Available in: .NET Framework 4.5+, .NET Standard 1.1+, and .NET Core 1.0+. It is currently the preferred approach, and is asynchronous and high performance. Use the built-in version in most cases, but for very old platforms there is a NuGet … Read more
Either you’ve retyped form.html correctly on SO and there is an error in you actual code (mainly calling the name field text), or you had it like this, then fixed it and the your browser is caching the old version. Easy way to check, in your browser view source on the form and check the … Read more
First, you’re going to want to look into the cURL library for PHP. http://php.net/manual/en/book.curl.php It’s basically a library to help you connect and communicate over various protocols, including HTTP using the POST method. There’s a very simple example on using the library on this page: http://php.net/manual/en/function.curl-init.php Second, you’re going to want to note the difference … Read more
The problem I had was that there is 4 submit buttons each with different name tag so the session will only store the last input button and will make it functional but for the others it will only refresh the page with no different because they are not being controlled by php code so to … Read more
Error #2 and #3: You have written a bit nonsense to the if() statement, mixed parts of what you intended to do. replace these two lines if(mysqli_num_rows((int)$sql_login>0)){ $result = mysqli_fetch_array($sql_login); with this one line if( $result = mysqli_fetch_array($sql_login) ){ Description of said one line code: If there is a record, $result will become an array, … Read more