Let’s re-write your program to make it a little clearer: #include<stdio.h> int main(void) { int arr[4] = {4,3,2,1}; int *p = arr; printf(“\n%d”, *(p+2)); return 0; } Now, *(p+2) is by definition the same as p[2]. Since p points to the first element of arr, then p[2] is the same as arr[2] which is equal … Read more
First of all, in code you have provided I do not see operator +, so compiler is absolutely right. The second point I do not understand is *(clsOriginalToCopy + lngIndex) expression… What your operator + should return? Pointer? Why not reference (considering your operator =)? Try to redesign your class, perhaps operator + is not … Read more
Yes, for gcc5.x and later specifically, that specific expression is optimized very early to just p, even with optimization disabled, regardless of any possible runtime UB. This happens even with a static array and compile-time constant size. gcc -fsanitize=undefined doesn’t insert any instrumentation to look for it either. Also no warnings at -Wall -Wextra -Wpedantic … Read more