[Solved] php $_POST[] not getting values [closed]
[ad_1] Why should $_POST be set? You’re using GET: <form id=”ffresult_sbox0″ …snip… method=”get” accept-charset=”utf-8″… ^^^^^^^^^^^^ 7 [ad_2] solved php $_POST[] not getting values [closed]
php
[Solved] How can i setup my php code to change my CSS background picture daily [closed]
[ad_1] You could either use the day of the week numbers, or day of the month numbers. Anything further than that you’ll probably need a database or a save file or something. This is the simplest way: //SHOW ONE IMAGE PER DAY OF THE WEEK FOR 7 IMAGES $dotw = new \DateTime(“NOW”); $dotwNum = $dotw->format(‘w’); … Read more
[Solved] Parameterized SELECT queries via PDO? [duplicate]
[ad_1] The PHP Manual has some good examples. For you: function user_login($username, $password) { $conn = connection_getConnection(); $sql = “SELECT `password` FROM `users` WHERE `username` = :username”; $stmt = $conn->prepare($sql, array(PDO::ATTR_CURSOR => PDO::CURSOR_FWDONLY)); $query = $stmt->execute(array(‘:username’ => $username)); $rows = $query->fetchAll(); if (empty($rows)) { } } 5 [ad_2] solved Parameterized SELECT queries via PDO? [duplicate]
[Solved] Unstoppable loop [closed]
[ad_1] Here, you will need to add your URL calling code tho. let arrUrls = [ [“URL1”, 4], [“URL2”, 10], [“URL3”, 8], [“URL4”, 9], [“URL5”, 6] ]; let sendNum = 0; function callUrl(url, rpt){ for (let i = 0; i < rpt; i++) { // calling code console.log(`called ${url} – ${i}/${sendNum}`); } }; let x … Read more
[Solved] Jquery add li class active
[ad_1] try this JQUERY first give the id to your ul <ul class=”nav nav-tabs” id=”nav_tabs”> then use jquery $(document).ready(function(){ $(‘ul#nav_tabs li a’).each(function(index, element) { var li = $(element).attr(‘href’); $(element).parent().removeClass(“active”); var filename = window.location.href.substr(window.location.href.lastIndexOf(“https://stackoverflow.com/”)+1); if(filename==li) { $(element).parent().addClass(“active”); } }); }); also you can use PHP as <?php $my_url = $_SERVER[‘REQUEST_URI’]; $page = substr($my_url, strrpos($my_url, “https://stackoverflow.com/”) + … Read more
[Solved] PHP swap between login/logout when user login/logout [closed]
[ad_1] Assuming $username is set somewhere you need to use <?php ?> tags to actually echo something: <?php if(isset($_SESSION[‘username’])): ?> <li><a href=”https://stackoverflow.com/questions/52586942/logout.php”>Logout</a> <?php echo $username; ?> </li> <?php else: ?> <li><a href=”login.php”>Login</a></li> <?php endif; ?> If $username is not set, use the session var: <?php if(isset($_SESSION[‘username’])): ?> <li><a href=”https://stackoverflow.com/questions/52586942/logout.php”>Logout</a> <?php echo $_SESSION[‘username’]; ?> </li> <?php … Read more
[Solved] extract 10 words from product description, into the page $title
[ad_1] From what I see in the comments, you will first have to make sure that your variable ($emlaklist) is already set, when you want to append it’s value to the $title variable. In general you might try to copy the code-part that starts with $emlaklist = .. to the place before your $title =, … Read more
[Solved] Convert structure to PHP array
[ad_1] Just like I said I would, here your very own Json Object parser. One word of warning, these kind of things can be more art then science so if your inputs vary from what was in your example, it could have issues. Given the small sample size (1 document) I make no guarantees on … Read more
[Solved] Access value from PHP array
[ad_1] Like this? $array->slug; It’s an object, not array. [ad_2] solved Access value from PHP array
[Solved] How to get recently updated MySQL field in a row using PHP (NOT ROW)
[ad_1] You will need to log the change in another table. Like changes with the attributes: id, table, attribute, old_value, new_value, datetime. Then, whenever something changes you add e.g. id, TESTING, last_name, Doe, DoKnow, 2015-03-06 12:34:56 Then you can use this table to show the latest changes. But in the long run and for big … Read more
[Solved] eval() is not allowed [closed]
[ad_1] Try $.parseJSON(data.indexOf(‘{‘) < 0 ? ‘{‘ + data + ‘}’ : data) eval is evil 2 [ad_2] solved eval() is not allowed [closed]
[Solved] remove subarray with php
[ad_1] the problem is you only unset a variable which has a copy of the value, you need to unset the corresponding element in the array. public function negativeKeywordsFilter($products, $negative_keywords){ $nk=explode(‘,’,$negative_keywords); foreach ($products[‘productItems’] as $key1 => $product){ foreach ($product as $key2 => $item){ foreach ($nk as $word){ if (stripos($item[‘name’],$word) !== false){ unset($products[‘productItems’][$key1][$key2]); } } } … Read more
[Solved] How do I import info from a database to my website? [closed]
[ad_1] $query = “SELECT * FROM ‘users’”; <?php $servername = “localhost”; $username = “username”; $password = “password”; $dbname = “myDB”; // Create connection $conn = new mysqli($servername, $username, $password, $dbname); // Check connection if ($conn->connect_error) { die(“Connection failed: ” . $conn->connect_error); } $sql = “SELECT * FROM users”; $result = $conn->query($sql); if ($result->num_rows > 0) … Read more
[Solved] Connect to Database and Insert data – Php & MySQL –
[ad_1] Try die() like following in your php file: $connection = mysqli_connect($host,$user,$password,$database); /* check connection */ if (mysqli_connect_errno()) { die(“Connect failed: “, mysqli_connect_error()); } $query=”insert into users(firstname, lastname)VALUES(‘”.$_REQUEST[‘nome’].”‘,'”.$_REQUEST[‘cognome’].”‘)”; if ($result = mysqli_query($connection ,$query)) { print(“Success!”); } 3 [ad_2] solved Connect to Database and Insert data – Php & MySQL –
[Solved] Access denied with localhost [closed]
[ad_1] open “config.inc.php” on your PMA folder. add this line to prompt the authentication before login $cfg[‘Servers’][$i][‘auth_type’] = ‘cookie’; /* $cfg[‘Servers’][$i][‘user’] = ‘root’; */ /* $cfg[‘Servers’][$i][‘password’] = ”; */ OR manually define your authentication by this line $cfg[‘Servers’][$i][‘auth_type’] = ‘config’; $cfg[‘Servers’][$i][‘user’] = ‘root’; $cfg[‘Servers’][$i][‘password’] = ‘yourpassword’; [ad_2] solved Access denied with localhost [closed]