Position of the first circle is described as x1 = x1_0 + vx1 * t y1 = y1_0 + vy1 * t where x10 is initial x-coordinate, vx1 is x-component of velocity vector, t is time. Make similar expression for the second circle center, build expression for squared distance and find time when squared distance … Read more
For a point p(i,j), it’s position in a matrix is equal to i*width+j where width is the width of the matrix. Hence the number of cells between two elemets is abs((i1*width+j1) – (i2*width+j2)). 1 solved How do i know number of cells between two points in array?
The problem with getting uncommented code “from a senior (buddy) of mine“, is that you have absolutely no guidance and zero reference for the algorithms used in the code. Many times this leaves you in a worse position than you would be in if you had taken the time to learn the math involved and … Read more