there’s a famous library for member system http://benedmunds.com/ion_auth/ the tutorial for it http://www.kylenoland.com/a-comprehensive-guide-to-securing-codeigniter-2-x-with-ben-edmunds-ion-auth/ you can find some articles on SO for that Registration with CodeIgniter Ion Auth wish they help. 6 solved Multiple step form ragistration in codeigniter [closed]
There is no native mapping of db table to email, so you have to first select, then retrieve then send $query = $this->db->query(“SELECT emailAddress from table”); //select email addresses $sendTo=array(); foreach ($query->result() as $row) //loop to build array { $sendTo[]=$row->emailAddress; //add to array } $this->email->to($sendTo);//send email Of course I have had to guess you tables … Read more
Im not sure exactly what you mean but I believe youre trying to grab data from your array to insert into ui tabs. This is what I would do in MVC: View: <li class=”tab” id=””><a href=”#<?php echo $variable; ?>”>Test</a></li> <li class=”tab” id=””><a href=”#<?php echo $variable; ?>”>Test</a></li> <li class=”tab” id=””><a href=”#<?php echo $variable; ?>”>Test</a></li> <li class=”tab” … Read more
it means you call for an array variable’s index ‘question’, and that index does not exist in that array. Maybe in function update(), $_POST[‘question’]. Not sure. You should provide the full error msg, like file and line. Also: the view if that’s the case. And make this sound more like a question. solved A PHP … Read more
you can place fallowing code wherever you want to load the view $this->load->view(‘viewname’); you can also pass the data to view as fallows $data[‘key’] = ‘this is data”;\ $this->load->view(‘viewname’,$data); and also you did not mention $ symbol before ‘p’ solved Loading views in conrtroller using CodeIgniter [closed]
HTML <div id=”dialogbox”></div> <div id=”content”> <p>name: <input type=”text” id=”name”/></p> <p>address: <input type=”text” id=”address”/></p> <p>Date: <input type=”text” id=”datepicker”/></p> <input type=”text” id=”test” /> </div> <input type=”submit” id=”mybutt” value=”next”> JQuery $(“#dialogbox”).dialog({ autoOpen:false, modal:true, title: “Use of Open event”, width:400, open: function( event, ui ) { } }); $(‘#mybutt’).click(function() { $(‘#dialogbox’).empty() var $clone=$(“#content”).clone() $(‘#dialogbox’).append($clone) $(“#dialogbox :input”).prop(“disabled”, true); $(‘#dialogbox’).dialog(‘open’); }); … Read more
Your solution is going to be a combination of an update and modifying the result using string literals and variables in MySQL. UPDATE <table_name> SET col_name1={expr1|DEFAULT} [, col_name2={expr2|DEFAULT}] … [WHERE where_condition] You are going to need to figure out how to “set” your column to the current value + a string literal. Your question does … Read more
In Your model add this method: public function getINFO(){ $query = $this->db->get_where(‘usuarios’, array(‘id’ => $this->session->userdata(‘id’))); if ($query->num_rows() > 0 ) { return $query->row_array(); } } See this link for more : https://www.codeigniter.com/user_guide/database/results.html#result-arrays 18 solved Conditional fetching data from a table
data returns an array .So replacing $udetails->comp_person_name with $udetails[‘0’]->comp_person_name solved the issue solved Trying to get property of non-object
First of all check your query using echo $this->db->last_query(); put this code in controller where you write $data[‘invoices’] and then check its working or not then use below code in your view part. <div class=”form-group”> <label for=”int”>Clients Id <?php echo form_error(‘clients_id’) ?></label> <select class=”form-control select2 select2-hidden-accessible” style=”width: 100%;”> <center><option selected=”selected”>— Select —</option></center> <?php foreach ($invoices … Read more
You should Change your if in your view to if(isset($images) && is_array($images)) that way if $images in undefined it will nto throw an error it will just skip that all together 4 solved Why is my gallery view page throwing up an error?
You passed username from jQuery with username: $(‘#userId’).val() not userId Try following with $this->input->post(‘username’) $username = strtolower(trim($this->input->post(‘username’))); Or change posted data index from jQuery: username to userId userId: $(‘#userId’).val() 0 solved Check Username or Password Availability Using AJAX on Codeigniter
The Users will be able to download only the views that you populate via php. CodeIgniter is a MVC (Model-View-Controller) framework for a reason, it encapsulates the business logic from what can be accessed by users. http://www.codeigniter.com/user_guide/overview/mvc.html solved How to prevent website download, so someone can’t download my full website [duplicate]
set $active_record = TRUE; $active_group = ‘default’; $active_record = TRUE; Note: that some CodeIgniter classes such as Sessions require Active Records be enabled to access certain functionality. its clearly stated here CodeIgniter Doc solved Fatal error: Call to undefined method CI_DB_pdo_driver::where() in
You can use the where_in method as a shortcut to multiple or-statements for the same column: $available_ids = [1, 2, 3]; $this->db->where_in(‘id’, $available_ids); // WHERE id IN (1, 2, 3) If you were looking to check multiple columns (the name is ‘Adam’ or the title is ‘Grand Poobah’ or the status is ‘Active’), you can … Read more