[Solved] write the folder path for it [closed]


@Monso, as per your provided inputs, expected outputs in problem & in comments, I’ve written the code to solve your problem.

In my case:

  • Input directory: C:\Users\pc-user\Desktop\Input

  • Output directory: C:\Users\pc-user\Desktop\Output

And I have 3 file A.txt, B.txt & C.txt inside Input directory with contents as follows.

You’ve to use your own paths as you’ve mentioned in problem.

» C:\\Users\\pc-user\\Desktop\\Input\\A.txt

This is %nice day%.
Program %20 files % 

enter image description here

» C:\\Users\\pc-user\\Desktop\\Input\\B.txt

This is my nice journey with % Rishikesh. Monso is % also %% here.

Monso %%%% is solving the Python problems % at % mor%ning.

enter image description here

» C:\\Users\\pc-user\\Desktop\\Input\\C.txt

This is % book.
This i%s i%%s a % boy%.
I kno%w P%y%t%%ho%n. %

enter image description here

Copy the below code, replace the value of input_dir and output_dir variables with your own paths and run.

» Python code

import glob 
import os 

def copy_files_to_output(input_dir, output_dir):
    # Creating a regex path for all text files inside Input directory
    input_dir_regex_path = os.path.join(input_dir, "*.txt");

    # Getting list of absolute paths of all the text files inside Input directory
    input_files_paths = glob.glob(input_dir_regex_path);

    # Iterating over a list of input file names
    for full_path in input_files_paths:
        # Get text file name from absolute path
        file_name = full_path.split('\\')[-1]

        # Reading input text file 
        # (Open file in read mode, 'r' is default here; the 2nd default parameter to open())
        # You do not need to close file (if you open as follows using with statement)
        with open(full_path) as in_file:
            # Creating full path name of output text file
            output_file_path = output_dir + "\\" + file_name;

            # Create a new file inside Output directory
            # 'w' specifies to open file in write mode
            with open(output_file_path, 'w') as out_file:
                # Get list of lines in text file
                all_lines = in_file.readlines();

                # Write all lines to a new file (inside Output directory)
                for line in all_lines:
                    # Replace all '%' characters present in line with '' 
                    line = line.replace('%', '');
                    out_file.write(line);


# Starting point
if __name__ ==  "__main__":
    try:
        # Code to be executed
        input_dir = "C:\\Users\\pc-user\\Desktop\\Input"; # Use your own path
        output_dir = "C:\\Users\\pc-user\\Desktop\\Output"; # Use your own path

        # Call copy_files_to_output() function
        copy_files_to_output(input_dir, output_dir);

        # Operation successful
        print("Copy operation successful");
    except Exception as error:
        # Code to be executed if any Exception occurs
        print("Exception occurred", error);

Once the above code executes successfully, it will write all text files present inside input_dir to output_dir. In my case, the contents inside Output directory looks like as mentioned below:

» C:\\Users\\pc-user\\Desktop\\Output\\A.txt

This is nice day.
Program 20 files  

enter image description here

» C:\\Users\\pc-user\\Desktop\\Output\\B.txt

This is my nice journey with  Rishikesh. Monso is  also  here.

Monso  is solving the Python problems  at  morning.

enter image description here

» C:\\Users\\pc-user\\Desktop\\Output\\C.txt

This is  book.
This is is a  boy.
I know Python. 

enter image description here

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solved write the folder path for it [closed]