[Solved] Why doesn’t this “is not” if statement work?

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To apply the logic of “not any” you would want to check if it is any of the valid results then invert. (NOR)

if not (diff == "1" or diff == "2" or diff == "3"):

Or applying DeMorgan’s theorem this would be equivelent to “not equal to 1 AND not equal to 2 AND not equal to 3”

if diff != "1" and diff != "2" and diff != "3":

of course python also has the in and not in operator which makes this much cleaner:

if diff not in ("1", "2", "3"):

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solved Why doesn’t this “is not” if statement work?