[Solved] Why doesn’t control enter the repeat() function? [closed]

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// Thanks for the help 

#include <stdio.h>
int repeat(int num) 
    {  
        scanf("%d",&num) ;
        if(num!=42)
        {
               printf("%d",num) ;
               repeat(num) ;
        }
    else
    {
        return num ;
    }
    getch() ;
    }

int main() {
       int num ;
       scanf("%d",&num) ;
       repeat(num) ;
       return 0;
}

solved Why doesn’t control enter the repeat() function? [closed]