[Solved] Why does the second call to name() print “Alex . n”?

Question

You took the variable n, declared statically inside name(), which pointed to a C-string " Justin ", then made it point to a C-string " Alex ".

So, naturally, when you inspect it later, it still points to a C-string " Alex ".

Remember, you declared it statically. That means every invocation of name() shares the same variable.

If function-static variables were to re-take their initialiser’s value every time you entered the function, there would be absolutely no point in making them static!

Accepted Answer

You took the variable n, declared statically inside name(), which pointed to a C-string " Justin ", then made it point to a C-string " Alex ".

So, naturally, when you inspect it later, it still points to a C-string " Alex ".

Remember, you declared it statically. That means every invocation of name() shares the same variable.

If function-static variables were to re-take their initialiser’s value every time you entered the function, there would be absolutely no point in making them static!