[Solved] Why does java throw an error when we use address and pointer for the following sorting program?

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Java is not C++.

You need to write swap differently in Java.

public static void swap(int[] a, int i, int j) {
    int t = a[i];
    a[i] = a[j];
    a[j] = t;
}

Java doesn’t support & and * unary operators.

On the plus side you don’t need to pass the length of an array

public static void bubble(int[] a) {
    for (int i = 0; i < a.length; i++) {

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solved Why does java throw an error when we use address and pointer for the following sorting program?