[Solved] what will be the output of following code in PHP? [closed]

Question

If you go through for you will find all the expressions are wrong –

For for($x++ ; $x==2 ; $x=2)

The first $x++ 0. – Incrementing an undefined variable sets it to 1, because it converts null to 0 when it’s used in an arithmetic context..

The second $x==2 will return false and the iteration will not be executed.

The third $x=2 will be executed at the end of each iteration.

So, the iteration will never be executed as $x==2 is always false.

And the output will be After the loop

Accepted Answer

If you go through for you will find all the expressions are wrong –

For for($x++ ; $x==2 ; $x=2)

The first $x++ 0. – Incrementing an undefined variable sets it to 1, because it converts null to 0 when it’s used in an arithmetic context..

The second $x==2 will return false and the iteration will not be executed.

The third $x=2 will be executed at the end of each iteration.

So, the iteration will never be executed as $x==2 is always false.

And the output will be After the loop