[Solved] what this code do [closed]

Question

As Qt is a GUI framework, I don’t understand why you should have to convert that function (I mean that nothing in Qt is going to stop you from using that function as-is).

Anyways:

bytes_to_encode is a character pointer, so *bytes_to_encode will return the character pointed to by bytes_to_encode. bytes_to_encode++ will return the pointer and then increment it (ie, make it point to the next location. *(bytes_to_encode++) combines both actions, ie it returns the character pointed to by bytes_to_encode and then increments the pointer, so that next time the next character is returned.

Accepted Answer

As Qt is a GUI framework, I don’t understand why you should have to convert that function (I mean that nothing in Qt is going to stop you from using that function as-is).

Anyways:

bytes_to_encode is a character pointer, so *bytes_to_encode will return the character pointed to by bytes_to_encode. bytes_to_encode++ will return the pointer and then increment it (ie, make it point to the next location. *(bytes_to_encode++) combines both actions, ie it returns the character pointed to by bytes_to_encode and then increments the pointer, so that next time the next character is returned.