[Solved] Valid or invalid barcodes [closed]

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It should be more like this because you have to input n times from the user:

int n = myScan.nextInt();
int[] bar = new int[n]; 
for (int i=0; i<bar.length; i++) {
        int n = myScan.nextInt(); 
        bar[i] = n; 
}

I consider using long instead of int in this situation.

Incase you want to store each digit in an array, you must use a multidimensional array which pretty much should be as below:

int number = myScan.nextInt();
int[][] bar = new int[number][12];

for (int i=0; i<bar.length; i++) {
    for (int j=0; j<bar[i].length; j++) {
            int n = myScan.nextInt(); 
            bar[i][j] = n; 
    }

And you will have a 2D array [x][] where x will be the index number from 0-(number-1) of the particular barcode and [x][0]-[x][11] will be the barcode digits at the index number x.

14

solved Valid or invalid barcodes [closed]