[Solved] Trouble starting an algorithm [closed]

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You will obviously compute the partial sums X.n and stop when X.n<4 and X.n+1>4.

To compute the partial sums, keep an accumulator variable and add the fractions one after the other

n= 0
S= 0
// Repeat the following instructions
    n+= 1
    S+= 1/(n+1) // Now, S = X.n

Remains to find the stopping condition. As the value of S goes increasing from 0, we will stop as soon as S exceeds 4. In other words, continue as long as S remains below 4.

n= 0
S= 0
while S < 4
    n+= 1
    S+= 1/(n+1) // Now, S = X.n

Translate that to C syntax.

Remains to look closer at the possibility that X.n = 4.

solved Trouble starting an algorithm [closed]