select ID,
-- returns a sequence without gaps for consecutive years
first_value(year) over (partition by ID order by year desc) - year +1 as x,
-- returns a sequence without gaps
row_number() over (partition by ID order by year desc) as rn
from Temp
e.g. for ID=1:
1 2016 1 1
1 2015 2 2
1 2012 5 3
1 2011 6 4
1 2010 7 5
As long as there’s no gap, both sequences increase the same.
Now check for equal sequences and count the rows:
with cte as
(
select ID,
-- returns a sequence without gaps for consecutive years
first_value(year) over (partition by ID order by year desc) - year + 1 as x,
-- returns a sequence without gaps
row_number() over (partition by ID order by year desc) as rn
from Temp
)
select ID, count(*)
from cte
where x = rn -- no gap
group by ID
Edit:
Based on your year zero comment:
with cte as
(
select ID, year,
-- returns a sequence without gaps for consecutive years
first_value(year) over (partition by ID order by year desc) - year + 1 as x,
-- returns a sequence without gaps
row_number() over (partition by ID order by year desc) as rn
from Temp
)
select ID,
-- remove the year zero from counting
sum(case when year <> 0 then 1 else 0 end)
from cte
where x = rn
group by ID
5
solved Sql query to Count Total Consecutive Years from latest year