[Solved] Sort out array of object using its value [duplicate]

by


Use String.localeCompare() with the numeric option to sort using possibility, but use - (minus) to get descending results. If the comparison returns 0 (equals), use localeCompare again to compare the names:

const array = [{"name":"fever","possibility":"20%"},{"name":"hiv","possibility":"25%"},{"name":"heart-attack","possibility":"20%"},{"name":"covid","possibility":"40%"}]

const result = array.sort((a, b) => 
  -a.possibility.localeCompare(b.possibility, undefined, { numeric: true })
  ||
  a.name.localeCompare(b.name)
)

console.log(result)

solved Sort out array of object using its value [duplicate]