[Solved] sort a list of lists by how many values each list has [duplicate]

by


Yes, you can use array sort method with a custom compare function.

listOLists.sort((a, b) => a.length > b.length ? 1 : -1)

If you want the order of same length item to be preserved you need to do the following,

listOLists.sort((a, b) => a.length - b.length)

Thanks to Patrick for pointing that out. For reference you can follow this this link.

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solved sort a list of lists by how many values each list has [duplicate]