The thing here is that your add
method shadows the i
attribute of the class with the i
variable declared as parameter. Thus, when using i
inside add
method, you’re using the i
parameter, not the i
attribute.
To note the difference, change the add
method to:
void add(int i) {
System.out.println(5+i);
System.out.println(5+this.i); //this will do the work for you
}
A good example of shadowing is used on class constructors:
public class SomeClass {
int x;
public SomeClass(int x) {
//this.x refers to the x attribute
//plain x refers to x parameter
this.x = x;
}
}
Follow up from comment:
got it , but what happens if i have the same member as i in JavaTest2 …and do the same this.i
This is called hiding and is well explained in Oracle’s Java tutorial: Hiding Fields
Example:
class JavaTest2 extends JavaTest {
int i = 10;
void add(int i) {
System.out.println(5+i);
System.out.println(5+this.i); //this will add 5 to i attribute in JavaTest2
System.out.println(5+super.i); //this will add 5 to i attribute in JavaTest
}
}
2
solved Simple inheritance but confusing