[Solved] Scanf clarification in c language

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Do not use scanf() or gets() function — use fgets() instead. But for the above question please find the answer.

int main() {
    char a[30];
    scanf ("%29[^\n]%*c", name);
    printf("%s\n", a);
    return 0;
}

Its also highly recommended like I told in the beginning to use fgets() instead. We clearly do not understand the weird requirement. I would have used the fgets() to read the character. 

fgets(a, size(a), stdin);

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solved Scanf clarification in c language