[Solved] Python – while loop three conditions [closed]

by


Your code could be a lot more readable if you restructured it slightly. Using DeMorgan’s laws we have that not A and not B and not C is the same as not (A or B or C). And since A or B or C is the same as any([A,B,C]) we can just take your first while and rewrite it as

while not any([ condition == 1, 
                condition1 > x, 
                condition2 > y ]):
   print("Hey")

We can see immediately why the loop isn’t running because one of those is True. Namely condition1 (which is 3) is greater than x (which is 2).

Similarly if we consider the second while loop rewritten as 

while not any([ condition == 1,
                condition1 > x ]):
   print("Hey")

Since condition equals 1, it fails on the first predicate. And even if condition didn’t equal 1, condition1 (which is 3) is greater than x (which is 2). So the second predicate also fails.

solved Python – while loop three conditions [closed]