[Solved] python calculator with two float numbers as parameters [closed]

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Hope this code may help you 

def add(a,b):
    print(a+b)
def subract(a,b):
    print(a-b)
def multipy(a,b):
    print(a*b)
def divide(a,b):
    print(a/b)
ch="y"
while ch=="y" or ch=="Y":
    x = float(input("first number : "))
    y = float(input("second number: "))
    print(".....MENU.......\n 1.Add\n 2.Subtract\n 3.Multiply\n 4.Divide\n")
    op=int(input("Enter your choice : "))
    if op==1:
        add(x,y)
    elif op==2:
        subract(x,y)
    elif op==3:
        multipy(x,y)
    elif op==4:
        divide(x,y)
    else: print("invalid Choice")
    ch=input("Do you want to continue?(Y/y) : ")

you may get output as:

    first number : 10
second number: 20
.....MENU.......
 1.Add
 2.Subtract
 3.Multiply
 4.Divide

Enter your choice : 1
30.0
Do you want to continue?(Y/y) : y
first number : 20.7
second number: 13.2
.....MENU.......
 1.Add
 2.Subtract
 3.Multiply
 4.Divide

Enter your choice : 2
7.5
Do you want to continue?(Y/y) : y
first number : 3.6
second number: 7.9
.....MENU.......
 1.Add
 2.Subtract
 3.Multiply
 4.Divide

Enter your choice : 3
28.44
Do you want to continue?(Y/y) : y
first number : 45
second number: 7
.....MENU.......
 1.Add
 2.Subtract
 3.Multiply
 4.Divide

Enter your choice : 4
6.428571428571429
Do you want to continue?(Y/y) : n

Process finished with exit code 0

this is a simple basic problem …
First you have to try your own code then if you get any error while solving. You have to ask Don’t just directly post your question..

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solved python calculator with two float numbers as parameters [closed]