[Solved] Performance consideration when using an out parameter and return value? [duplicate]

Question

The out keyword causes arguments to be passed by reference. This is like the ref keyword, except that ref requires that the variable be initialized before it is passed. To use an out parameter, both the method definition and the calling method must explicitly use the out keyword. For example:

class OutExample
{
    static void Method(out int i)
    {
        i = 44;
    }
    static void Main()
    {
        int value;
        Method(out value);
        // value is now 44
    }
}

Reference of out

Reference 2

Return
The return statement terminates execution of the method in which it appears and returns control to the calling method. It can also return an optional value. If the method is a void type, the return statement can be omitted.

If the return statement is inside a try block, the finally block, if one exists, will be executed before control returns to the calling method.

class ReturnTest
    {
        static double CalculateArea(int r)
        {
            double area = r * r * Math.PI;
            return area;
        }

        static void Main()
        {
            int radius = 5;
            double result = CalculateArea(radius);
            Console.WriteLine("The area is {0:0.00}", result);

            // Keep the console open in debug mode.
            Console.WriteLine("Press any key to exit.");
            Console.ReadKey();
        }
    }
    // Output: The area is 78.54

Return Reference

Accepted Answer